// UVa 11547 - Automatic Answer
#include <iostream>
#include <cmath>
using namespace std;
#define type signed long long
int main() {
int cases;
for (cin >> cases; cases; cases--) {
double n;
cin >> n;
double d = (n * 567 / 9 + 7492) * 235 / 47 - 498;
type s = (type) (abs(d / 10));
cout << (s % 10) << endl;
}
return 0;
}
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