// UVa 11547 - Automatic Answer #include <iostream> #include <cmath> using namespace std; #define type signed long long int main() { int cases; for (cin >> cases; cases; cases--) { double n; cin >> n; double d = (n * 567 / 9 + 7492) * 235 / 47 - 498; type s = (type) (abs(d / 10)); cout << (s % 10) << endl; } return 0; }
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