// UVa 190 - Circle Through Three Points
#include <iostream>
#include <cmath>
#include <stdio.h>
using namespace std;
struct point {
double x, y;
};
struct line {
double a, b, c;
};
line points_to_line(point p, point q) {
line l;
l.a = p.y - q.y;
l.b = q.x - p.x;
l.c = -l.a * p.x - l.b * p.y;
return l;
}
line perpendicular(line l, point p) {
line per;
per.a = -l.b;
per.b = l.a;
per.c = -per.a * p.x - per.b * p.y;
return per;
}
point intersection(line l1, line l2) {
point p;
p.y = (l2.c * l1.a - l1.c * l2.a) / (l1.b * l2.a - l2.b * l1.a);
p.x = (l2.c * l1.b - l1.c * l2.b) / (l1.a * l2.b - l2.a * l1.b);
return p;
}
double dist(point p, point q) {
return sqrt((p.x - q.x) * (p.x - q.x) + (p.y - q.y) * (p.y - q.y));
}
point middle(point p, point q) {
point m = { (p.x + q.x) / 2, (p.y + q.y) / 2 };
return m;
}
void print(double d) {
char ch = d < 0 ? '-' : '+';
printf("%c %.3f", ch, abs(d));
}
int main() {
point p1, p2, p3;
while (cin >> p1.x >> p1.y >> p2.x >> p2.y >> p3.x >> p3.y) {
line side1 = points_to_line(p1, p2);
line side2 = points_to_line(p2, p3);
point mid1 = middle(p1, p2);
point mid2 = middle(p2, p3);
line per1 = perpendicular(side1, mid1);
line per2 = perpendicular(side2, mid2);
point c = intersection(per1, per2);
double r = dist(c, p1);
// equation 1
printf("(x ");
print(-c.x);
printf(")^2 + (y ");
print(-c.y);
printf(")^2 = %.3f^2\n",r);
// equation 2
double e = -2 * c.x;
double f = -2 * c.y;
double g = -r * r + c.x * c.x + c.y * c.y;
printf("x^2 + y^2 ");
print(e);
printf("x ");
print(f);
printf("y ");
print(g);
printf(" = 0\n\n");
}
return 0;
}
Sunday, June 7, 2015
UVa 190 - Circle Through Three Points
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